A) 1100
B) 11,000
C) 550
D) 5500
Correct Answer: D
Solution :
[d] Given: Diameter of water tap \[=\frac{2}{\sqrt{\pi }}\,cm\] \[\therefore \] Radius, \[r=\frac{1}{\sqrt{\pi }}\times {{10}^{-2}}\,m\] \[\frac{dm}{dt}=\rho AV\] \[\frac{15}{5\times 60}={{10}^{3}}\times \pi {{\left( \frac{1}{\sqrt{\pi }} \right)}^{2}}\times {{10}^{-4}}V\] \[\Rightarrow \,\,\,V=0.05\,m\text{/}s\] Reynold's number, \[{{R}_{e}}=\frac{\rho \,V\,r}{n}\] \[=\frac{10\times 0.5\times \frac{2}{\sqrt{\pi }}{{10}^{-2}}}{{{10}^{-3}}}\cong 5500\]You need to login to perform this action.
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