A) 392
B) 31.6
C) 278
D) 156
Correct Answer: A
Solution :
[a] Mohr's salt is \[FeS{{O}_{4}}.{{(N{{H}_{4}})}_{2}}S{{O}_{4}}.6{{H}_{2}}O.\] \[F{{e}^{2+}}\] present in it is oxidized to \[F{{e}^{3+}}.\] So, we have, \[F{{e}^{2+}}\xrightarrow{{}}F{{e}^{3+}}+e\] Thus, equivalent mass \[\text{=}\frac{\text{Formula}\,\,\text{mass}}{\text{1}}\] \[=392\]You need to login to perform this action.
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