A) 5 and 4.42
B) 4 and 4.00
C) 5 and 3.42
D) 3 and 5.42
Correct Answer: A
Solution :
[a] Given \[{{\pi }_{ob}}=10.8\,atm\] \[{{\pi }_{nor}}=CST=0.10\times 0.0821\times 298=2.446\] now experimental value of\[(i)\] \[\text{=}\frac{\text{Observed}\,\,\text{osmotic}\,\,\text{pressure}}{\text{Normal}\,\,\text{osmotic}\,\,\text{pressure}}\] \[=\frac{10.8}{2.446}=4.42\]You need to login to perform this action.
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