A) N A B R\[\omega \]
B) N A B
C) N A B R
D) N A B\[\omega \]
Correct Answer: D
Solution :
[d] \[e=-\frac{d\phi }{dt}=-\frac{d(N\overrightarrow{B}.\overrightarrow{A})}{dt}\] \[=-N\frac{d}{dt}(BA\,\,\cos \,\omega t)=NBA\omega \,\,\sin \omega t\] \[\Rightarrow \]\[{{e}_{\max }}=NBA\omega \]You need to login to perform this action.
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