A) 1-bromo-2-methylbutane
B) 1-bromo-3-methylbutane
C) 2-bromo-3-methylbutane
D) 2-bromo-2-methylbutane
Correct Answer: D
Solution :
[d] The order of substitution in different alkanes is \[3{}^\circ >2{}^\circ >1{}^\circ \] Thus the bromination of 2-methyl butane mainly gives 2-Bromo - 2 - methyl butane \[C{{H}_{3}}-\underset{\text{2-methyl}\,\,\text{butane}}{\mathop{C{{H}_{2}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,}}\,-C{{H}_{3}}\xrightarrow{B{{r}_{2}}}\]You need to login to perform this action.
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