A) 0.8 M
B) 1.6 M
C) 1.2 M
D) 10.0M
Correct Answer: B
Solution :
[b] \[\underset{0.4\,\,moles}{\mathop{HCl}}\,{{H}^{+}}+\underset{0.4\,\,moles}{\mathop{C{{l}^{-}}}}\,\] \[\underset{0.2\,\,moles}{\mathop{CaC{{l}_{2}}}}\,C{{a}^{2+}}+\underset{2\times 0.2=0.4\,\,moles}{\mathop{2C{{l}^{-}}}}\,\] Total \[C{{l}^{-}}moles=0.4+0.4=0.8\,moles\] \[Molarity=\frac{Moles}{Vol.in\,\,L}\] \[\therefore \] Molarity of \[C{{l}^{-}}=\frac{0.8}{0.5}=1.6\,\,M.\]You need to login to perform this action.
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