A) 13.3
B) 5.0
C) 9.4
D) 6.7
Correct Answer: B
Solution :
[b] Angular momentum, mvr\[=I\omega \] Moment of Inertia (I) of cubical block is given by \[I=m\left( \frac{{{R}^{2}}}{6}+{{\left( \frac{R}{\sqrt{2}} \right)}^{2}} \right)\] \[\therefore \] \[\omega =\frac{m.2\frac{R}{2}}{m\left[ \frac{{{R}^{2}}}{6}+{{\left( \frac{R}{\sqrt{2}} \right)}^{2}} \right]}\] \[\Rightarrow \]\[\omega =\frac{12}{8R}=\frac{3}{2\times 0.3}=\frac{10}{2}=5\,\,rad/s.\]You need to login to perform this action.
You will be redirected in
3 sec