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NEET Sample Paper NEET Sample Test Paper-88

  • question_answer
    A glass flask is filled up to a mark with 50 cc of mercury at \[9\times {{10}^{-6}}\text{/ }\!\!{}^\circ\!\!\text{ C}\] If the flask and contents are heated to \[38{}^\circ C,\] how much mercury-will be above the mark? (\[\alpha \]for glass is \[9\times {{10}^{-6}}\text{/ }\!\!{}^\circ\!\!\text{ C}\] and coefficient of real expansion of mercury is \[180\times {{10}^{-6}}/{}^\circ C)\]

    A) 0.85 cc

    B)                    0.46 cc

    C) 0.153 cc

    D)                                                                                                                    0.05 cc

    Correct Answer: C

    Solution :

    [c] Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by \[\Delta V={{V}_{0}}\left[ {{\gamma }_{L}}-{{\gamma }_{g}} \right]\Delta \theta =V\left[ {{\gamma }_{L}}-3{{\alpha }_{g}} \right]\Delta \theta \] \[=50\,[180\times {{10}^{-6}}-3\times 9\times {{10}^{-6}}](38-18)\] \[=0.153\,cc\]


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