A triangular block of mass M with angles \[30{}^\circ ,\]\[60{}^\circ \]and \[90{}^\circ \] rest with its \[30{}^\circ -90{}^\circ \] side on a horizontal table. A cubical block of mass m rests on \[60{}^\circ -30{}^\circ \]side. The acceleration which M must have relative to the table to keep m stationary relative to the triangular block is (assuming frictionless contact)
A)\[g\]
B) \[g/\sqrt{2}\]
C)\[g/\sqrt{3}\]
D) \[g/\sqrt{5}\]
Correct Answer:
C
Solution :
[c] Use result, \[a=\text{gtan}\,\theta ,\]\[a=g\tan 30{}^\circ =g/\sqrt{3}\]