question_answer

A network of six identical capacitors, each of capacitance C is made as shown in the figure. The equivalent capacitance between points A and B is

A) C/4                  

B)        3C/4

C) 4C/3    

D)        3C

Correct Answer: C

Solution :

[c] The network is equivalent to Therefore equivalent capacitance \[=[2C\,series\,C]//\,[C\,series\,2C]\] \[=2\left( \frac{2C\times C}{2C+C} \right)=\frac{4C}{3}\]