A) about \[3.2\times {{10}^{10}}\,J\]
B) about \[6.4\times {{10}^{10}}\,J\]
C) about \[6.4\times {{10}^{6}}\,J\]
D) None of these
Correct Answer: B
Solution :
[b] \[E=\frac{1}{2}m{{v}_{e}}^{2}=\frac{1}{2}\times 1000\times {{(11.2\times {{10}^{3}})}^{2}}\] \[=6.4\times {{10}^{10}}\,J\,(approx.)\]
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