NEET Sample Paper NEET Sample Test Paper-88

  • question_answer
    A closed spherical surface of radius R encloses an electric dipole. The net electric flux through the surface is

    A) zero                  

    B)        \[2q.4\pi {{R}^{2}}\]

    C) \[\frac{q}{{{\varepsilon }_{0}}}\]                      

    D)        \[\frac{2q}{{{\varepsilon }_{0}}}\]

    Correct Answer: A

    Solution :

    [a] According to the Gauss's law, the net electric flux through the closed spherical surface is equal to the total charge enclosed by the surface divided by \[{{\varepsilon }_{0}},\] i.e., \[{{\phi }_{E}}=\frac{-q+q}{{{\varepsilon }_{0}}}=0\]


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