NEET Sample Paper NEET Sample Test Paper-88

  • question_answer
    For a given material, the Young's modulus is 2.4 times that of rigidity modulus, the Poission's ratio is

    A) 0.2       

    B)        0.4  

    C) 12                    

    D)        2.4

    Correct Answer: A

    Solution :

    [a] The relation between Y,\[\eta \]and\[\sigma \]is as follows: \[Y=2\eta (1+\sigma )\] \[\sigma =\frac{Y}{2\eta }-1=0.2\]


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