A) 79.4 J
B) 97.54 J
C) 105.25 J
D) None of these
Correct Answer: A
Solution :
[a] Force of friction acting \[=\mu mg=0.15\times 60\times 9.8\,N\] Distance = 0.9 m Work done \[=0.15\times 60\times 9.8\times 0.9\] \[=79.4\,joule\]
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