A) \[4125\,A{}^\circ \]
B) \[3000\,A{}^\circ \]
C) \[6000\,A{}^\circ \]
D) \[2062\,A{}^\circ \]
Correct Answer: B
Solution :
[b] Since work function for a metal surface is \[W=\frac{hc}{{{\lambda }_{0}}}\] where \[{{\lambda }_{0}}\] is threshold wavelength or cut-off wavelength for a metal surface. here \[W=4.125,eV=4.125\times 1.6\times {{10}^{-19}}Joule\] so \[{{\lambda }_{0}}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{4.125\times 1.6\times {{10}^{-19}}}=3000\,\overset{\circ }{\mathop{\text{A}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
