A) 1020
B) 1018
C) 1022
D) 1019
Correct Answer: A
Solution :
[a] Given, \[\lambda =600\,nm,\] Power \[=0.5\,kW,\]t\[=60\,ms\] Power P \[=\frac{nhc}{\lambda t}\]\[\Rightarrow \]\[n=\frac{p\lambda t}{hc}\] \[=0.5\times {{10}^{3}}\times \frac{660\times {{10}^{-9}}\times 60\times {{10}^{-3}}}{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}\] \[=100\times {{10}^{18}}={{10}^{20}}\]You need to login to perform this action.
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