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NEET Sample Paper NEET Sample Test Paper-88

  • question_answer
    A phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is \[\pi /2.\] The wave velocity is

    A) 384 m/s

    B)        768 m/s

    C) 250 m/s

    D)        154 m/s

    Correct Answer: A

    Solution :

    [a] Phase difference \[=\frac{2\pi }{\lambda }\times \] path difference \[\frac{\pi }{2}=\frac{2\pi }{\lambda }\times 0.8\] \[\Rightarrow \]\[\lambda =0.8\,m\times 4=3.2\,m\] velocity \[=\lambda \times v=3.2\times 120=384\,m/s\]


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