A) 50%
B) 30%
C) 21%
D) 10%
Correct Answer: D
Solution :
[d] \[{{T}_{1}}=2\pi \sqrt{\frac{\ell }{g}}\] Length \[\ell \] increases from \[\ell \]to \[1.21\,\ell .\] \[{{T}_{2}}=2\pi \sqrt{\frac{1.21\ell }{g}}=1.1{{T}_{1}}\] Thus % increase in time period = 10%.
You need to login to perform this action.
You will be redirected in
3 sec
