A) C/4
B) 3C/4
C) 4C/3
D) 3C
Correct Answer: C
Solution :
[c] The network is equivalent to Therefore equivalent capacitance \[=[2C\,series\,C]//\,[C\,series\,2C]\] \[=2\left( \frac{2C\times C}{2C+C} \right)=\frac{4C}{3}\]You need to login to perform this action.
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