A) \[\frac{\pi }{18}Nm\]
B) \[\frac{2\pi }{15}Nm\]
C) \[\frac{\pi }{12}Nm\]
D) \[\frac{\pi }{15}Nm\]
Correct Answer: D
Solution :
[d] \[\tau \times \Delta t={{L}_{0}}\] \[\{\therefore since\,{{L}_{f}}=0\}\] \[=\tau \times \Delta t=I\omega \] or \[=\tau \times 60=2\times 2\times 60\pi /60\] \[\left( \therefore \,\,\,\,f=60rpm\,\,\,\,\therefore \omega =2\pi f=2\pi f=2\pi \times \frac{60}{60} \right)\] \[\tau =\frac{\pi }{15}N-m\]You need to login to perform this action.
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