A) \[{{T}_{({{H}_{2}})}}={{T}_{({{N}_{2}})}}\]
B) \[{{T}_{({{H}_{2}})}}>{{T}_{({{N}_{2}})}}\]
C) \[{{T}_{({{H}_{2}})}}<{{T}_{({{N}_{2}})}}\]
D) \[{{T}_{({{H}_{2}})}}=\sqrt{7}{{T}_{({{N}_{2}})}}\]
Correct Answer: C
Solution :
[c] \[\frac{{{U}_{{{H}_{2}}}}}{{{U}_{{{N}_{2}}}}}=\sqrt{\frac{{{T}_{{{H}_{2}}}}\times 28}{{{T}_{{{N}_{2}}}}\times 2}}=\sqrt{7}\]\[\Rightarrow \]\[\frac{{{T}_{{{H}_{2}}}}}{{{T}_{{{N}_{2}}}}}=\frac{1}{2}\] \[{{T}_{{{N}_{2}}}}=2{{T}_{{{H}_{2}}}}\] \[\therefore \]\[{{T}_{{{N}_{2}}}}>2{{T}_{{{H}_{2}}}}\]
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