A) \[22\,km/s\]
B) \[11\,km/s\]
C) \[\frac{11}{\sqrt{2}}\,km/s\]
D) \[11\sqrt{2}\,km/s\]
Correct Answer: B
Solution :
[b] Since escape velocity \[\left( {{v}_{e}}=\sqrt{2g}{{R}_{e}} \right)\] is independent of angle of projection, so it will not change.You need to login to perform this action.
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