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NEET Sample Paper NEET Sample Test Paper-88

  • question_answer
    0.45 g of acid of molecular weight 90 was neutralized by 20 ml. of a 0.5N caustic potash. The basicity of an acid is

    A) 1                     

    B)        2    

    C) 3                     

    D)        4

    Correct Answer: B

    Solution :

    [b] No. of equivalents of caustic sdoda \[=20\times {{10}^{-3}}\times 0.5={{10}^{-2}}\] \[\therefore \] No. of equivalents of acid\[={{10}^{-2}}\] Also, \[\frac{\text{Wt}\text{.}\,\text{of}\,\text{acid }\!\!\times\!\!\text{ Basicity}}{\text{MW}}\text{=No}\text{.}\,\text{of}\,\text{equiv}\text{.}\] \[\Rightarrow \]\[\frac{0.45}{90}\times x={{10}^{-2}}\]\[\Rightarrow \]\[x=2\]


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