NEET Sample Paper NEET Sample Test Paper-88

  • question_answer
    Equivalent conductance of an electrolyte containing NaF at infinite dilution is \[90.1\,Oh{{m}^{-1}}c{{m}^{2}}.\] If NaF is replaced by KF what is the value of equivalent conductance?

    A) \[90.1\,Oh{{m}^{-1}}c{{m}^{2}}\]

    B)        \[111.2\,Oh{{m}^{-1}}c{{m}^{2}}\]

    C) \[0\]                 

    D)        \[222.4\,Oh{{m}^{-1}}c{{m}^{2}}\]

    Correct Answer: A

    Solution :

    [a] Because at infinite dilution the equivalent conductance of strong electrolytes furnishing same number of ions is same.


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