A) \[\frac{{{u}^{2}}}{g}\]
B) \[\frac{{{u}^{2}}}{4g}\]
C) \[\frac{2{{u}^{2}}}{g}\]
D) \[\frac{{{u}^{2}}}{2g}\]
Correct Answer: D
Solution :
[d] At maximum height, \[v=u\,\cos \,45{}^\circ =\frac{u}{\sqrt{2}};\] \[{{a}_{c}}=g\] \[r=\frac{{{\left( \frac{u}{\sqrt{2}} \right)}^{2}}}{g}=\frac{{{u}^{2}}}{2g}\]You need to login to perform this action.
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