A) \[-0.04\,V\]
B) \[+0.04\,V\]
C) \[+0.30\,V\]
D) \[+1.56\,V\]
Correct Answer: D
Solution :
[d] \[E_{cell}^{0}=E_{Zn/Z{{n}^{2+}}}^{0}+E_{C{{u}^{2+}}/Cu}^{0}\,\,first\,cell\] \[1.10=E_{Zn/Z{{n}^{2+}}}^{0}+0.34\] \[E_{Zn/Z{{n}^{2+}}}^{0}=0.76\,\,V\] \[E_{cell}^{0}=E_{Cu/C{{u}^{2+}}}^{0}+E_{A{{g}^{+}}/Ag}^{0}\,\,\text{second}\,\,cell\] \[0.46=-0.34+E_{A{{g}^{+}}/Ag}^{0}\] \[E_{A{{g}^{+}}/Ag}^{0}=0.80\,\,V\] For third cell \[E_{cell}^{0}=E_{Zn/Z{{n}^{2+}}}^{0}+E_{A{{g}^{+}}/Ag}^{0}\] \[=0.76+0.80\] \[=+1.56\,\,V\]You need to login to perform this action.
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