A) 2/3 mole of \[Mn{{O}_{4}}^{-}\] and 1 /3 mole of \[Mn{{O}_{2}}\]
B) 113 mole of \[Mn{{O}_{4}}^{-}\] and 2/3 mole of \[Mn{{O}_{2}}\]
C) 1/3 mole of \[M{{n}_{2}}{{O}_{7}}\] and 1/3 mole of \[Mn{{O}_{2}}\]
D) 2/3 mole of \[M{{n}_{2}}{{O}_{7}}\] and 1/3 mole of \[Mn{{O}_{2}}\]
Correct Answer: A
Solution :
[a] \[3Mn{{O}_{4}}^{2-}+2{{H}_{2}}O\to Mn{{O}_{2}}+2MnO_{4}^{-}+4O{{H}^{-}}\] or \[MnO_{4}^{2-}+\frac{2}{3}{{H}_{2}}O\to \frac{1}{3}Mn{{O}_{2}}+\frac{2}{3}MnO_{4}^{-}+\frac{4}{3}O{{H}^{-}}\]
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