A) Reversible
B) Irreversible
C) Spontaneous
D) Non spontaneous
Correct Answer: C
Solution :
[c] \[\Delta H=-2.5\times {{10}^{3}}cal\] \[\Delta S=7.4\,cal\] \[\Delta G=\Delta H-T\Delta S\] \[=-2.5\times {{10}^{3}}-298\times 7.4=-4705.2\,Cal.\] \[\Delta G=-\] ive; so process is spontaneous \[\Delta G=0,\] Equilibrium \[\Delta G=+\] ive; Non-spontaneousYou need to login to perform this action.
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