A) \[\frac{M}{2}\]
B) \[\frac{M}{4}\]
C) \[M\]
D) \[0\]
Correct Answer: D
Solution :
[d] 1 L of 1 M \[CuS{{O}_{4}}=1\,\,mol\] of \[C{{u}^{2+}}\] \[C{{u}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Cu\] 2 F of electricity will convert dil \[C{{u}^{2+}}\] into \[Cu\] hence \[[CuS{{O}_{4}}]=0\] Thus, [d]You need to login to perform this action.
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