A) 100 K
B) 150 K
C) 195 K
D) 255 K
Correct Answer: B
Solution :
[b] Since the gas expands adiabatically (i.e., no change in enthalpy) so the heat is totally converted into work. For the gas, \[{{C}_{V}}=20\,J/K.\] Thus, \[20\,J\] of heat is required for \[1{}^\circ \] change in temperature of the gas. Heat change involved during the process i.e., work done = 3 kJ =3000 J. Change in temperature \[\frac{3000}{20}K=150\,K\] Initial temperature = 300 K Since, the gas expands so the temperature decreases and thus final temperature is \[300\text{ }-150=\text{ }150\text{ }K\]You need to login to perform this action.
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