A) \[[A{{g}^{+}}]=1.8\times {{10}^{-7}}M;\] \[[P{{b}^{2}}^{+}]=1.7\times {{10}^{-6}}M\]
B) \[[A{{g}^{+}}]=1.8\times {{10}^{-11}}M;\] \[[P{{b}^{2}}^{+}]=8.5\times {{10}^{-5}}M\]
C) \[[A{{g}^{+}}]=1.8\times {{10}^{-9}}M;\] \[[P{{b}^{2}}^{+}]=1.7\times {{10}^{-3}}M\]
D) \[[A{{g}^{+}}]=1.8\times {{10}^{-11}}M;\] \[[P{{b}^{2}}^{+}]=8.5\times {{10}^{-4}}M\]
Correct Answer: C
Solution :
[c] \[{{K}_{sp}}=[A{{g}^{+}}][C{{l}^{-}}]\] \[1.8\times {{10}^{-10}}=[A{{g}^{+}}][0.1]\] \[[A{{g}^{+}}]=1.8\times {{10}^{-9}}M\] \[{{K}_{sp}}=[P{{b}^{+2}}]{{[C{{l}^{-}}]}^{2}}\] \[1.7\times {{10}^{-5}}=[P{{b}^{+2}}]{{[0.1]}^{2}}\] \[[P{{b}^{+2}}]=1.7\times {{10}^{-3}}M\]You need to login to perform this action.
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