A) \[C{{l}^{+}}\]
B) \[AlC{{l}_{4}}^{-}\]
C) \[C{{H}_{3}}^{+}\]
D) \[AlC{{l}_{2}}^{+}\]
Correct Answer: C
Solution :
[c] \[C{{H}_{3}}Cl\underset{Electrophile}{\mathop{+AlC{{l}_{3}}}}\,\xrightarrow{{}}C{{H}_{3}}^{+}+AlC{{l}_{4}}^{-}\]You need to login to perform this action.
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