A) 206 Hz, 412 Hz
B) 824 Hz, 1648 Hz
C) 412 Hz, 824 Hz
D) 206 Hz, 824 Hz
Correct Answer: B
Solution :
[b] \[\frac{v}{4\ell }=412,\] when cut into two equal pieces, frequency of closed pipe of half the length \[=\frac{v}{4(\ell /2)}=\frac{2v}{4\ell }=2\times 412=824\,\,Hz\] frequency of open pipe of half the length \[=\frac{v}{2(\ell /2)}=4\times 412=1648\,\,Hz\]You need to login to perform this action.
You will be redirected in
3 sec