A) \[V/2\]
B) \[V/\sqrt{2}\]
C) \[2\,\,V\]
D) \[4\,\,V\]
Correct Answer: D
Solution :
[d] Since \[{{v}_{rms}}\] is doubled by increasing the temp. so by \[{{v}_{rms}}=\sqrt{\frac{3KT}{m}},\] the temp. increase by four times. Now for constant pressure \[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\] \[{{V}_{1}}=V,\]\[{{T}_{1}}=T{}^\circ K,\]\[{{T}_{2}}=4T{}^\circ K,\]\[{{V}_{2}}=?\] \[{{V}_{2}}=4V\]You need to login to perform this action.
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