A) \[s{{p}^{2}},\] \[s{{p}^{3}}\] and \[s{{p}^{2}}\] respectively
B) \[sp,\] \[s{{p}^{2}}\] and \[s{{p}^{3}}\] respectively
C) \[s{{p}^{2}},\] \[sp\] and \[s{{p}^{3}}\] respectively
D) \[s{{p}^{2}},\] \[s{{p}^{3}}\] and \[sp\] respectively
Correct Answer: B
Solution :
[b] \[NO_{2}^{+}=1/2[5+0+0-1]=2\,sp;\] \[NO_{2}^{-}=1/2[5+0+0-1]=3\,s{{p}^{2}};\] \[NO_{4}^{+}=1/2[5+4+0-1]=4\,s{{p}^{3}}\]You need to login to perform this action.
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