A) \[6h\]
B) \[12h\]
C) \[24h\]
D) \[128h\]
Correct Answer: B
Solution :
Number of half-life after which intensity of radiation becomes \[\frac{1}{64}\] of initial is given by \[\frac{1}{64}={{\left( \frac{1}{2} \right)}^{n}}\] \[\Rightarrow \] \[n=6\] Required time \[=6\times 2=12h\]You need to login to perform this action.
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