A) \[20.0\,V\]
B) \[25.6\,V\]
C) \[31.9\,V\]
D) \[53.5\,V\]
Correct Answer: B
Solution :
We have, \[V={{({{V}^{2}}R+V_{L}^{2})}^{1/2}}\] \[={{(20\times 20+6\times 16)}^{1/2}}=25.6V\]You need to login to perform this action.
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