A) \[{{180}^{o}}\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{{{(2L)}^{2}}}\]
B) \[{{90}^{o}},\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{{{L}^{2}}}\]
C) \[{{180}^{o}},\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{2{{L}^{2}}}\]
D) \[{{180}^{o}},\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{Q}^{2}}}{{{L}^{2}}}\]
Correct Answer: A
Solution :
The position of the balls in no gravity space will be as shown (The ball will attain a position at which angle between the threads would be \[{{180}^{o}}\]) As, \[\theta ={{180}^{o}},\] Than, force \[=\frac{1}{4\pi {{\varepsilon }_{0}}},\frac{{{Q}^{2}}}{{{(2L)}^{2}}}\]You need to login to perform this action.
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