A) at a horizontal distance of \[1m\] from free end of the spring
B) at a horizontal distance of \[2m\] from free and of the springs
C) vertically below the edge on which the mass is resting
D) at a horizontal distance of \[\sqrt{2}m\] from free end of the spring
Correct Answer: A
Solution :
From work-energy theorem \[\frac{1}{2}(1000){{\left( \frac{5}{100} \right)}^{2}}=\frac{1}{2}m{{v}^{2}}\] \[V=\sqrt{\frac{5}{2}}\] Horizontal range, \[X=V\sqrt{\frac{2h}{g}}=1m\] (as \[h=2m\])You need to login to perform this action.
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