A) \[\frac{\omega m}{(m+2m)}\]
B) \[\frac{\omega (m+2m)}{m}\]
C) \[\frac{\omega (m-2m)}{(m+2m)}\]
D) \[\frac{\omega m}{(m+m)}\]
Correct Answer: A
Solution :
As there is no external torque on the body and hence there is no change in angular momentum. \[L=L'\] \[m{{R}^{2}}\omega =(m{{R}^{2}}+2m{{R}^{2}})\omega '\] \[\omega '=\frac{m\omega }{m+2m}\]You need to login to perform this action.
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