A) 1A
B) 2A
C) 4A
D) 6A
Correct Answer: C
Solution :
Here, from the circuit on right New resistance \[=\frac{3}{2}\Omega \] (\[\because \] \[2\,\Omega \]and \[6\,\Omega \] in parallel) Then by Kirchhoff?s law \[6=\frac{3}{2}i\] \[\Rightarrow \] \[i=4A\]You need to login to perform this action.
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