A) 300N
B) zero
C) \[150\sqrt{3N}\]
D) 150 N
Correct Answer: C
Solution :
As, velocity towards the wall is \[V\,\,sin\,\theta i\]and the velocity outward to the wall is \[V\,\,sin\,\theta \,(-i)\] Now \[|\Delta P|\,=V\,\sin \theta -(-\sin \theta )\] \[=2V\,\sin \theta \] \[F=\frac{2m\upsilon \sin \theta }{t}\] \[\left( as,\,\,F=\frac{\Delta p}{\Delta t} \right)\] \[=\frac{2\times 3\times 10\sin {{60}^{o}}}{0.2}=150\sqrt{3}N\]You need to login to perform this action.
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