A) \[4:1\]
B) \[1:4\]
C) \[1:2\]
D) \[2:1\]
Correct Answer: A
Solution :
Let mole of \[HCOOH=x\] mole of \[{{H}_{2}}{{C}_{2}}{{O}_{4}}=y\] \[\underset{x}{\mathop{HCOOH}}\,+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\underset{x}{\mathop{CO}}\,+{{H}_{2}}O+{{H}_{2}}S{{O}_{4}}\] \[\underset{y}{\mathop{{{H}_{2}}{{C}_{2}}{{O}_{4}}}}\,+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\underset{y}{\mathop{CO}}\,+\underset{y}{\mathop{C{{O}_{2}}SOl4}}\,+{{H}_{2}}O+{{H}_{2}}S{{O}_{4}}\] Total gaseous products \[=x+2y\] Only \[C{{O}_{2}}\] is absorbed by \[KOH,\]y mole \[\therefore \] \[\frac{y}{x+2y}=\frac{1}{6}\] \[x+2y=6y\] \[x=4y\] \[\frac{x}{y}=\frac{4}{1}\]You need to login to perform this action.
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