A) \[-8.12\]
B) \[+8.612\]
C) \[-37.83\]
D) \[-16.13\]
Correct Answer: D
Solution :
\[Ag{{I}_{(s)}}+{{e}^{-}}A{{g}_{(s)}}+{{I}^{-}}\,;\,\,\,{{E}^{o}}=-0.152\] \[\underset{Ag{{I}_{(s)}}\xrightarrow{{}}A{{g}^{+}}+{{I}^{-}}\,\,;\,\,\,\,\,\,\,\,\,\,\,{{E}^{o}}=-0.952}{\mathop{\underset{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}{\mathop{A{{g}_{(s)}}\xrightarrow{{}}A{{g}^{+}}+{{e}^{-}}\,;\,\,\,\,\,\,{{E}^{o}}=-0.8}}\,}}\,\] \[E_{cell}^{o}=\frac{0.059}{1}\log \,{{K}_{SP}}\] \[-0.952=\frac{0.059}{1}\log {{K}_{SP}}\] \[\log \,\,{{K}_{SP}}=\frac{-0.952}{0.059}=-16.135\]You need to login to perform this action.
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