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NEET Sample Paper NEET Sample Test Paper-8

  • question_answer
    A small block of mass \[0.1\text{ }kg\] is pressed against a horizontal spring fixed at one end to compress the spring through \[5.0cm\]as shown. The spring constant is \[100N/m.\]. When released the WE block moves horizonally till it leaves the spring. It will hit the ground 2m below the spring.

    A)  at a horizontal distance of \[1m\] from free end of the spring

    B)  at a horizontal distance of \[2m\] from free and of the springs

    C)  vertically below the edge on which the mass is resting

    D)  at a horizontal distance of \[\sqrt{2}m\] from free end of the spring

    Correct Answer: A

    Solution :

    From work-energy theorem \[\frac{1}{2}(1000){{\left( \frac{5}{100} \right)}^{2}}=\frac{1}{2}m{{v}^{2}}\]                 \[V=\sqrt{\frac{5}{2}}\] Horizontal range, \[X=V\sqrt{\frac{2h}{g}}=1m\] (as  \[h=2m\])


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