A) zero
B) K
C) \[K/2\]
D) \[K/\sqrt{2}\]
Correct Answer: C
Solution :
As we know that kinetic energy at the top. \[K'=\frac{1}{2}m{{u}^{2}}{{\cos }^{2}}\theta =\frac{K}{2}\]You need to login to perform this action.
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