A) 2
B) 4
C) 6
D) 10
Correct Answer: B
Solution :
From photoelectric equation, \[e{{V}_{0}}={{(K\varepsilon )}_{\max }}=4eV\] \[\Rightarrow \] \[{{V}_{0}}=4\] Volt (Here \[{{V}_{0}}\] is stopping potential).You need to login to perform this action.
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