2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-90

  • question_answer
    When light of wavelength 300 nm (nanometre) falls on a photoelectric emitter, photoelectrons are emitted. For another emitter, however, light of 600 nm wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

    A) 1 : 2     

    B)                    2 : 1  

    C) 4 : 1                 

    D)         1 : 4

    Correct Answer: B

    Solution :

    [b] \[{{W}_{0}}=\frac{hc}{{{\lambda }_{0}}}\] or \[{{W}_{0}}\propto \frac{1}{{{\lambda }_{0}}};\]  \[\Rightarrow \]\[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{600}{300}=2\]


You need to login to perform this action.
You will be redirected in 3 sec spinner