A) 33.33
B) 35.0
C) 30.0
D) 66.67
Correct Answer: B
Solution :
[b] \[S{{O}_{2}}C{{l}_{2}}(g)S{{O}_{2}}(g)+C{{l}_{2}}(g)\] \[\alpha \,%=\frac{D-d}{d(y-1)}\times 100\] (y=2) \[D=\frac{\text{molar mass of}\,S{{O}_{2}}C{{l}_{2}}}{2}=\frac{135}{2}=67.5;\] \[d=50.0(\text{given})\] \[\alpha \,%=\frac{67.5-50.0}{50.0(2-1)}\times 100=35%\]You need to login to perform this action.
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