A) 1.85
B) 1.5
C) 1.37
D) 3
Correct Answer: C
Solution :
[c] Centre of mass \[{{x}_{cm}}=\frac{x}{2}\frac{(\rho x)\left( \frac{x}{2} \right)\frac{1}{2}+\rho y\left( \frac{y}{2} \right)}{\rho (x+y)}\] \[\Rightarrow \]\[\frac{1}{2}+\frac{y}{x}=\frac{{{y}^{2}}}{{{x}^{2}}}\] \[\therefore \] \[\frac{BC}{AB}=\frac{y}{x}=\frac{1+\sqrt{3}}{2}=1.37\]You need to login to perform this action.
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